Section: Mathematical Operators
y = a + b
where a and b are n-dimensional arrays of numerical type. In the
first case, the two arguments are the same size, in which case, the
output y is the same size as the inputs, and is the element-wise the sum
of a and b. In the second case, either a or b is a scalar,
in which case y is the same size as the larger argument,
and is the sum of the scalar added to each element of the other argument.
The type of y depends on the types of a and b using the type
promotion rules. The types are ordered as:
uint8 - unsigned, 8-bit integers range [0,255]
int8 - signed, 8-bit integers [-127,128]
uint16 - unsigned, 16-bit integers [0,65535]
int16 - signed, 16-bit integers [-32768,32767]
uint32 - unsigned, 32-bit integers [0,4294967295]
int32 - signed, 32-bit integers [-2147483648,2147483647]
float - 32-bit floating point
double - 64-bit floating point
complex - 32-bit complex floating point
dcomplex - 64-bit complex floating point
C. Numerical overflow rules are also the same as C.
If a is a scalar, then the output is computed via
On the other hand, if b is a scalar, then the output is computed via
int32 is the default type used for
integer constants (same as in C), hence the output is the
same type:
--> 3 + 8 ans = 11 --> quit
Next, we use the floating point syntax to force one of the arguments
to be a double, which results in the output being double:
--> 3.1 + 2
ans =
5.1000
-->
quit
Note that if one of the arguments is complex-valued, the output will be complex also.
--> a = 3 + 4*i
a =
3.0000 + 4.0000i
--> b = a + 2.0f
b =
5.0000 + 4.0000i
-->
quit
If a complex value is added to a double, the result is
promoted to dcomplex.
--> b = a + 2.0
b =
5.0000 + 4.0000i
-->
quit
We can also demonstrate the three forms of the addition operator. First the element-wise version:
--> a = [1,2;3,4] a = 1 2 3 4 --> b = [2,3;6,7] b = 2 3 6 7 --> c = a + b c = 3 5 9 11 --> quit
Then the scalar versions
--> c = a + 1 c = 2 3 4 5 --> c = 1 + b c = 3 4 7 8 --> quit