| Safe Haskell | Safe-Inferred | 
|---|---|
| Language | Haskell2010 | 
Control.Monad.IO.Unlift
Description
Please see the README.md file for information on using this package at https://www.stackage.org/package/unliftio-core.
Synopsis
- class MonadIO m => MonadUnliftIO (m :: Type -> Type) where- withRunInIO :: ((forall a. m a -> IO a) -> IO b) -> m b
 
- newtype UnliftIO (m :: Type -> Type) = UnliftIO {}
- askUnliftIO :: MonadUnliftIO m => m (UnliftIO m)
- askRunInIO :: MonadUnliftIO m => m (m a -> IO a)
- withUnliftIO :: MonadUnliftIO m => (UnliftIO m -> IO a) -> m a
- toIO :: MonadUnliftIO m => m a -> m (IO a)
- wrappedWithRunInIO :: MonadUnliftIO n => (n b -> m b) -> (forall a. m a -> n a) -> ((forall a. m a -> IO a) -> IO b) -> m b
- liftIOOp :: MonadUnliftIO m => (IO a -> IO b) -> m a -> m b
- class Monad m => MonadIO (m :: Type -> Type) where
Documentation
class MonadIO m => MonadUnliftIO (m :: Type -> Type) where #
Monads which allow their actions to be run in IO.
While MonadIO allows an IO action to be lifted into another
 monad, this class captures the opposite concept: allowing you to
 capture the monadic context. Note that, in order to meet the laws
 given below, the intuition is that a monad must have no monadic
 state, but may have monadic context. This essentially limits
 MonadUnliftIO to ReaderT and IdentityT transformers on top of
 IO.
Laws. For any function run provided by withRunInIO, it must meet the
 monad transformer laws as reformulated for MonadUnliftIO:
- run . return = return 
- run (m >>= f) = run m >>= run . f 
Instances of MonadUnliftIO must also satisfy the following laws:
- Identity law
- withRunInIO (\run -> run m) = m
- Inverse law
- withRunInIO (\_ -> m) = liftIO m
As an example of an invalid instance, a naive implementation of
 MonadUnliftIO (StateT s m) might be
withRunInIO inner =
  StateT $ \s ->
    withRunInIO $ \run ->
      inner (run . flip evalStateT s)
This breaks the identity law because the inner run m would throw away
 any state changes in m.
Since: 0.1.0.0
Methods
withRunInIO :: ((forall a. m a -> IO a) -> IO b) -> m b #
Convenience function for capturing the monadic context and running an IO
 action with a runner function. The runner function is used to run a monadic
 action m in IO.
Since: 0.1.0.0
Instances
| MonadUnliftIO IO # | |
| Defined in Control.Monad.IO.Unlift | |
| MonadUnliftIO m => MonadUnliftIO (IdentityT m) # | |
| Defined in Control.Monad.IO.Unlift | |
| MonadUnliftIO m => MonadUnliftIO (ReaderT r m) # | |
| Defined in Control.Monad.IO.Unlift | |
newtype UnliftIO (m :: Type -> Type) #
The ability to run any monadic action m a as IO a.
This is more precisely a natural transformation. We need to new
 datatype (instead of simply using a forall) due to lack of
 support in GHC for impredicative types.
Since: 0.1.0.0
askUnliftIO :: MonadUnliftIO m => m (UnliftIO m) #
Capture the current monadic context, providing the ability to
 run monadic actions in IO.
See UnliftIO for an explanation of why we need a helper
 datatype here.
Prior to version 0.2.0.0 of this library, this was a method in the
 MonadUnliftIO type class. It was moved out due to
 https://github.com/fpco/unliftio/issues/55.
Since: 0.1.0.0
askRunInIO :: MonadUnliftIO m => m (m a -> IO a) #
Same as askUnliftIO, but returns a monomorphic function
 instead of a polymorphic newtype wrapper. If you only need to apply
 the transformation on one concrete type, this function can be more
 convenient.
Since: 0.1.0.0
withUnliftIO :: MonadUnliftIO m => (UnliftIO m -> IO a) -> m a #
Convenience function for capturing the monadic context and running
 an IO action. The UnliftIO newtype wrapper is rarely needed, so
 prefer withRunInIO to this function.
Since: 0.1.0.0
toIO :: MonadUnliftIO m => m a -> m (IO a) #
Convert an action in m to an action in IO.
Since: 0.1.0.0
Arguments
| :: MonadUnliftIO n | |
| => (n b -> m b) | The wrapper, for instance  | 
| -> (forall a. m a -> n a) | The inverse, for instance  | 
| -> ((forall a. m a -> IO a) -> IO b) | The actual function to invoke  | 
| -> m b | 
A helper function for implementing MonadUnliftIO instances.
Useful for the common case where you want to simply delegate to the
underlying transformer.
Note: You can derive MonadUnliftIO for newtypes without this helper function
in unliftio-core 0.2.0.0 and later.
Example
newtype AppT m a = AppT { unAppT :: ReaderT Int (ResourceT m) a }
  deriving (Functor, Applicative, Monad, MonadIO)
-- Same as `deriving newtype (MonadUnliftIO)`
instance MonadUnliftIO m => MonadUnliftIO (AppT m) where
  withRunInIO = wrappedWithRunInIO AppT unAppTSince: 0.1.2.0
liftIOOp :: MonadUnliftIO m => (IO a -> IO b) -> m a -> m b #
A helper function for lifting IO a -> IO b functions into any MonadUnliftIO.
Example
liftedTry :: (Exception e, MonadUnliftIO m) => m a -> m (Either e a) liftedTry m = liftIOOp Control.Exception.try m
Since: 0.2.1.0
class Monad m => MonadIO (m :: Type -> Type) where #
Monads in which IO computations may be embedded.
 Any monad built by applying a sequence of monad transformers to the
 IO monad will be an instance of this class.
Instances should satisfy the following laws, which state that liftIO
 is a transformer of monads:
Methods
Lift a computation from the IO monad.
 This allows us to run IO computations in any monadic stack, so long as it supports these kinds of operations
 (i.e. IO is the base monad for the stack).
Example
import Control.Monad.Trans.State -- from the "transformers" library printState :: Show s => StateT s IO () printState = do state <- get liftIO $ print state
Had we omitted liftIO
• Couldn't match type ‘IO’ with ‘StateT s IO’ Expected type: StateT s IO () Actual type: IO ()
The important part here is the mismatch between StateT s IO () and IO ()
Luckily, we know of a function that takes an IO a(m a): liftIO
> evalStateT printState "hello" "hello" > evalStateT printState 3 3